Parameter
| Model | sp12/220-1000LC | sp24/220-1000LC | sp48/220-1000LC |
| Continuous Power | 1000W | ||
| Surge Power | 2000W | ||
| Frequency | 50HZ±0.5HZ or 60HZ±0.5HZ | ||
| Wave Form | Pure Sine Wave | ||
| AC Regulation | THD<3%(Linear Load) | ||
| Output Efficiency | 92% | ||
| DC Voltage | DC12V | DC24V | DC48V |
| AC Voltage | 220VAC or 230VAC or 240VAC ±5% | ||
| No Load Current Draw | 0.8a | 0.4a | 0.2a |
| DC Voltage Range | 10-15.5V | 20-31V | 40-61V |
| Low Voltage Alarm | 10.5±0.5V | 21±0.5V | 42±1V |
| Low Voltage Shut Down | 10±0.5V | 20±0.5V | 40±1V |
| Over Voltage Shut Down | 15.5±0.5V | 31±0.5V | 61±1V |
| Low Voltage Recovery | 13±0.5V | 24±0.5V | 48±1V |
| Over Voltage Recovery | 14.8V±0.5V | 29V±0.5V | 59V±1V |
| Charging Voltage | 14.6V±0.2V | 29.2V±0.3V | 58.4V±0.5V |
| Floating Charge Voltage | 13.8V±0.2V | 27.6V±0.3V | 55V±0.5V |
| Charging Current | ≤15A | ≤8A | ≤5A |
| Transfer Time | ≤9MS | ≤9MS | ≤9MS |
| Grid Input Draw | 220VAC or 230VAC or 240VAC ±10% | ||
| Protection | Low Voltage/Over Voltage | LED Alarm and Automatic Recovery. | |
| Overload | LED Alarm and Automatic Recovery. | ||
| Over Temperature | LED Alarm and Automatic Recovery. | ||
| Short Circuit | LED Alarm and Automatic Recovery. | ||
| Working Temperature | -10°- +50° | ||
| Storage Temperature | -30°- +70° | ||
1. High efficiency:
The battery with the same capacitance, higher efficiency, longer use time. Reliable inverter use the most advanced technology to raise the efficiency to 90%, save more energy, more environmental protection.
2. Protection systems:
Thermal protection, Overload protection, Over Voltage protection, Under Voltage protection, Low Voltage protection alarm. Inverter comes with an LED light to indicate the problem.
3.What's the difference between an inverter and inverter with charger?
An inverter converts DC (battery) power into AC power and then passes it along to connected equipment. An inverter with charger does the same thing, except that it is connected to an AC power source to continuously charge the attachedbatteries when AC utility power is available. In the case of a power outage, the inverter will automatically switch to battery power to provide power to connected equipment.
4. How do I charge the batteries?
Inverter/Chargers must also be connected to AC utility power for their charging feature to work.
5. How fast will the inverter respond to a power outage?
During a blackout in the utility grid, inverters with chargers automatically switch from utility
power to battery backup power.the inverter will transfer from utility to battery power in about 9 milliseconds
|
Package Size |
550*235*150(mm) |
|
N.W/G.W |
4.30/5.1(kg) |
|
Cooling Way |
Intelligent Cooling Fan |
(1)Short circuit production.
When the load is short circuit, the inverter will stop working.
(2)High temperature production.
When the use environment is stuffy, the heat of the inverter can not be radiated. The temperature is above the rated temperature, the inverter will stop working.
(3) High voltage protections.
The battery voltage is above the rated voltage of the inverter, the inverter will stop working.
(4)Low voltage protections
The battery’s voltage falls during the usage. When it is lower than the rated voltage, the inverter will automatically cut the input voltage for the self protection.
(5) Surge protection.
It can avoid the DC high voltage’s surging attack upon the electronic components inside.
(6) Overload protection
When the appliances’ power is higher than the inverter’s power, the inverter will stop working for self protection.
(7) Over current Protection
When the appliances’ current is bigger than the inverter’ current, the protection components on the board will be cut automatically for self protection.
(8)Fuse protection.
When the appliance’s resistance is bigger than inverter’s, the fuses on the socket will be automatically cut off for self protection.
(9)Reverse protection
It can avoid the accidents of burning the inverter if the positive and the negative poles are reverse connected.
Yueqing Swipower Co.,Ltd. specializes in producing 19 rack mount inverter, pure sine wave inverter, pure sinewave inverter by pass, pure sine wave inverter with charger. Quality trusted by the user, the current product sales throughout the country most of the provinces. Through independent research and development to master the high-frequency switching power supply system is the core technology, is the few customization to meet customer requirements, to provide complete integrated power system products and solutions for businesses.
How to choose suitable inverter ?
If your load is resistive loads, such as: bulbs, you can choose a modified wave inverter. But if it is inductive loads and capacitive loads, we recommend using pure sine wave inverter. For example: fans, precision instruments, air conditioner, fridge, coffee machine, computer, and so on. Modified wave can be started with some inductive loads, but effect for load using life, because capacitive loads and inductive loads need highquality power.
How do I choose the size of the inverter ?
Different types of load demand for power are different. You can view the load power values to determine the size of the inverter. Notice: resistive load: you can choose the same power as the load. Capacitive loads: according to the load, you can choose 2-5 times power. Inductive loads: according to the load, you can choose 4-7 times power.
How connection between batteries and an inverter ?
We usually believe that cables connecting battery terminal to inverter shorter is better. If you are just standard cable should be less than 0.5M, but should correspond to the polarity of the batteries and inverter-side outside. If you want to lengthen the distance between battery and inverter, please contact us and we will calculate the recommended cable size and length. Due to long distances using a cable connection, there will be a reduced voltage, which means that the inverter voltage would be far below the battery terminal voltage, this inverter will appear under voltage alarm conditions.
How to calculate the load of working hours requires configuration of the battery size ?
We will usually have a formula to calculate, but it is not hundred percent accurate, because there is also the battery's condition, the old batteries have some loss, so this is only a reference value: Work hours = battery capacity * battery voltage *0.8/load power (H= AH*V*0.8/W)
